Answer 2.13
Let us assume that the link is a baseband
link, that is, the frequency response extends from dc to 12 kHz.
- For a baseband channel the symbol rate can be up to
twice the available bandwidth, hence this channel can support up to 24000 symbols/second. With
binary signalling, this is equal to a bit rate of 24 kbps.
- The ShannonHartley equation gives us the required
relationship between channel capacity in bps, bandwidth and signal to noise ratio as
follows:
Channel capacity C = B.log2(S/N + 1) bps
Therefore C = 12.103log2(10000 + 1) bps
= 159.45 kbps